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(3^-7)*3x=27
We move all terms to the left:
(3^-7)*3x-(27)=0
We multiply parentheses
9x^2-21x-27=0
a = 9; b = -21; c = -27;
Δ = b2-4ac
Δ = -212-4·9·(-27)
Δ = 1413
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1413}=\sqrt{9*157}=\sqrt{9}*\sqrt{157}=3\sqrt{157}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-3\sqrt{157}}{2*9}=\frac{21-3\sqrt{157}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+3\sqrt{157}}{2*9}=\frac{21+3\sqrt{157}}{18} $
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